jdk1.8 lambda表达式过滤重复的对象-白红宇

jdk1.8 lambda表达式过滤重复的对象

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发布时间：2019-06-29

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//操作类public class BizAgentAudit {    private String supplierOrgId;    private int age;    private String name;        public BizAgentAudit() {        super();    }    public String getSupplierOrgId() {        return supplierOrgId;    }    public void setSupplierOrgId(String supplierOrgId) {        this.supplierOrgId = supplierOrgId;    }    public int getAge() {        return age;    }    public void setAge(int age) {        this.age = age;    }    public String getName() {        return name;    }    public void setName(String name) {        this.name = name;    }        }//JDK1.8新特性遍历//方案1： List
    
      rejectList = new ArrayList<>();     BizAgentAudit temp1 = new BizAgentAudit();     BizAgentAudit temp2 = new BizAgentAudit();     BizAgentAudit temp3 = new BizAgentAudit();     BizAgentAudit temp4 = new BizAgentAudit();    //偷懒，没给对象赋值，你们得赋值哦     rejectList.add(temp1);     rejectList.add(temp2);     rejectList.add(temp3);     rejectList.add(temp4);    //去重 rejectList = rejectList.stream() .collect(Collectors.collectingAndThen(Collectors.toCollection(()-> new         TreeSet<> (Comparator.comparing(BizAgentAudit::getSupplierOrgId))), ArrayList::new));//方案2：

    List
    
      rejectList = new ArrayList<>();        BizAgentAudit temp1 = new BizAgentAudit();        BizAgentAudit temp2 = new BizAgentAudit();             BizAgentAudit temp3 = new BizAgentAudit();     //偷懒，没给对象赋值，你们得赋值哦              rejectList.add(temp1);              rejectList.add(temp2);              rejectList.add(temp3);    rejectList .stream().filter( distinctByKey(o -> o.getSupplierOrgId()) ).forEach( p ->{           //业务处理操作        }    );

    //自定义根据对象属性过滤重复的对象    private 
    
      Predicate
     
       distinctByKey(Function
       keyExtractor) {        Map
      
        seen = new ConcurrentHashMap<>();        return t -> seen.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;    }